The hydrogen ion, H+, binds with the enzyme (E) to activate it in the form EH. The

Question:

The hydrogen ion, H+, binds with the enzyme (E–) to activate it in the form EH. The hydrogen ion, H+, also binds with EH to deactivate it by forming EH2+
H++E−←→EHK1=(EH)(H+)(E−)H++EH←→EH2+K2=(EH2+)(H+)(EH)EH+S←→EHS→EH+P,KM=(EHS)(EH)(S)
where E– and EH2+ are inactive.
a. Determine whether the preceding sequence can explain the optimum in enzyme activity with pH shown in Figure P9-13B.

Figure P9-13B -rs pH