The K f for [Cu(en) 2 ] 2+ is much larger than the one for [Cu(NH3) 4

Question:

The Kf for [Cu(en)2]2+ is much larger than the one for [Cu(NH3)4]2+.

This difference is primarily an entropy effect. Explain why and calculate the difference between the ΔS° values at 298 K for the complete dissociation of the two complex ions.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  answer-question
Question Posted: