Two compounds, A and B, have the molecular formula C 3 H 9 N. One isomer has
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Two compounds, A and B, have the molecular formula C3H9N. One isomer has no hydrogen atoms bonded to the nitrogen atom and has a boiling point of 2.9 °C. The other isomer (boiling point of 47.8 °C) has two hydrogen atoms bonded to the nitrogen atom, and the carbon atoms and nitrogen atom are in a straight chain. Neither structure contains a ring. Draw the Lewis structure of both compounds. Compare the types of intermolecular forces for each and use them to explain the differences in the boiling point of the two compounds.
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Related Book For
Chemistry Principles And Practice
ISBN: 9780534420123
3rd Edition
Authors: Daniel L. Reger, Scott R. Goode, David W. Ball
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