Calculate the depth below the surface of water at which the pressure due to the weight of
Question:
Calculate the depth below the surface of water at which the pressure due to the weight of the water equals 1.00 atm.
Strategy
We begin by solving the equation P=hρg for depth h:
Then we take P to be 1.00 atm and ρto be the density of the water that creates the pressure.
Transcribed Image Text:
P h == pg
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