Suppose an ice skater, such as the one in Figure 10.21, is spinning at 0.800 rev/s with

Question:

Suppose an ice skater, such as the one in Figure 10.21, is spinning at 0.800 rev/s with her arms extended. She has a moment of inertia of 2.34 kg - m2 with her arms extended and of 0.363 kg - m2 with her arms close to her body. (These moments of inertia are based on reasonable assumptions about a 60.0-kg skater.)

(a) What is her angular velocity in revolutions per second after she pulls in her arms? 

(b) What is her rotational kinetic energy before and after she does this?

(a) (0) L = 100 (b) L = 1'0'

Strategy 

In the first part of the problem, we are looking for the skater’s angular velocity after she has pulled in her arms. To find this quantity, we use the conservation of angular momentum and note that the moments of inertia and initial angular velocity are given. To find the initial and final kinetic energies, we use the definition of rotational kinetic energy given byKErot 1 == lav. =

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