Suppose that in a situation like that in Example 25.2, light goes from air to diamond and

Question:

Suppose that in a situation like that in Example 25.2, light goes from air to diamond and that the incident angle is 30.0°. Calculate the angle of refraction θ2 in the diamond.


Strategy

Again the index of refraction for air is taken to be n1 = 1.00, and we are given θ1 = 30.0. We can look up the index of refraction for diamond in Table 25.1, finding n2 = 2.419. The only unknown in Snell's law is θ2, which we wish to determine.


Data from Table 25.1

Medium Gases at 0C, 1 atm Air Carbon dioxide Hydrogen Oxygen Liquids at 20C Benzene Carbon disulfide Carbon

Data from Example 25.2

Find the index of refraction for medium 2 in Figure 25.12(a), assuming medium 1 is air and given the incident angle is 30.0 and the angle of refraction is 22.0°.


Strategy

The index of refraction for air is taken to be 1 in most cases (and up to four significant figures, it is 1.000). Thus n = 1.00 here. From the given information, θ1 = 30.0° and θ2 = 22.0°. With this information, the only unknown in Snell's law is n, so that it can be used to find this unknown.


Data from Figure 25.12

Incident ray Grass (n) (a) Sidewalk (n) Refracted ray Refracted ray Grass () (b) Sidewalk (n.) Incident ray

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