The lightbulb in Figure P18.10 is 50 cm from a mirror. It emits 1.5 W of visible
Question:
The lightbulb in Figure P18.10 is 50 cm from a mirror. It emits 1.5 W of visible light. A small barrier blocks the direct rays of light from the bulb from reaching a sensor 70 cm to the right, but not the reflected rays. What is the light intensity at the sensor?
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Step by Step Answer:
To find the light intensity at the sensor we can use the inverse square law which states that the in...View the full answer
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Related Book For 
College Physics A Strategic Approach
ISBN: 9780134779218
4th Edition
Authors: Randall D. Knight, Brian Jones
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