A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a
Question:
A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a nail. When pulled to the side and released, the hoop swings back and forth as a physical pendulum. The moment of inertia of a hoop for a rotational axis passing through its edge is I = 2MR2. What is the period of oscillation of the hoop?
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
The period of oscillation of a physical pendulum can be calculated using the formula T 2I mgh Where ...View the full answer
Answered By
Felix Onchweri
I have enough knowledge to handle different assignments and projects in the computing world. Besides, I can handle essays in different fields such as business and history. I can also handle both short and long research issues as per the requirements of the client. I believe in early delivery of orders so that the client has enough time to go through the work before submitting it. Am indeed the best option that any client that can think about.
5+ Reviews
19+ Question Solved
Related Book For 
College Physics A Strategic Approach
ISBN: 9780321595492
2nd Edition
Authors: Randall D. Knight, Brian Jones, Stuart Field
Question Posted:
