AB is a diameter of the circle (x 3) + (y 2) = 5, where
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AB is a diameter of the circle (x − 3)² + (y − 2)² = 5, where A is (2, 0).
D(5, 3) lies on the circle.
Show that triangle ABD is right angled at D.
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Since AB is the diameter of the circle it passes through the center of the circle C3 ...View the full answer
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Related Book For
Complete Pure Mathematics 1 For Cambridge International AS & A Level
ISBN: 9780198427438
2nd Edition
Authors: Jean Linsky, Brian Western, James Nicholson
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