In the Diffie-Hellman protocol, each participant selects a secret number (x) and sends the other participant (alpha^{x}

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In the Diffie-Hellman protocol, each participant selects a secret number \(x\) and sends the other participant \(\alpha^{x} \bmod q\) for some public number \(\alpha\). What would happen if the participants sent each other \(x^{\alpha}\) for some public number \(\alpha\) instead? Give at least one method Alice and Bob could use to agree on a key. Can Eve break your system without finding the secret numbers? Can Eve find the secret numbers?

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