Given that x 2 + 10x + 36 (x + a) 2 + b, where a and

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Given that x2 + 10x + 36 (x + a)2 + b, where a and b are constants,

a. Find the value of a and the value of b.

b. Hence show that the equation x2 + 10x + 36 = 0 has no real roots.  The equation x2 + 10x + k = 0 has equal roots.

c. Find the value of k.

d. For this value of k, sketch the graph of y = x2 + 10x + k, showing the coordinates of any points at which the graph meets the coordinate axes.

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