x 2 14x + 1 = (x + p) 2 + q, where p and q

Question:

x2 − 14x + 1 = (x + p)2 + q, where p and q are constants.

a. Find the values of p and q.

b. Using your answer to part a, or otherwise, show that the solutions to the equation x2 − 14x + 1 = 0 can be written in the form r ± s√3 , where r and s are constants to be found.

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