Invert the plane stress form of Hookes law (7.2.2) and express the stresses in terms of the

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Invert the plane stress form of Hooke’s law (7.2.2) and express the stresses in terms of the strain components:

0x = dy Txy E -(ex + vey) 1- E 1- E 1+v -(ey + vex) exy

Equation 7.2 .2

ex ey ez =/=/= (0x (ox - voy) exy 1 E (Oy - vox) - / / (0x + 0) = ay) 1+v E -Txy: V -1 - 7 (ex + ey) exz =

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