A photon of energy E = 511 keV is scattered backwards by an electron at rest.
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A photon of energy Eγ = 511 keV is scattered backwards by an electron at rest. What is the value of the energy of the scattered photon? What is the value if the target electron were moving against the photon with energy Te = 511 keV?
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We first find an expression valid in both cases Call E 1 and p 1 E 1 the ene...View the full answer
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Related Book For
Introduction to Elementary Particle Physics
ISBN: 978-1107050402
2nd edition
Authors: Alessandro Bettini
Question Posted:
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