Consider an electronproton collision at HERA. The energy of the electron beam is E e = 28
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Consider an electron–proton collision at HERA. The energy of the electron beam is Ee = 28 GeV and of the proton beam Ep = 820 GeV. One electron is observed to scatter at the angle θ = 120° and its energy is measured to be E'e = 223 GeV. Calculate the centre of mass energy and the kinematical variables Q2, x, ν and W.
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a b The fourmomentum of the initial proton is P E p P p and the four...View the full answer
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Related Book For
Introduction to Elementary Particle Physics
ISBN: 978-1107050402
2nd edition
Authors: Alessandro Bettini
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