Consider an electronproton collision at HERA. The energy of the electron beam is E e = 28

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Consider an electron–proton collision at HERA. The energy of the electron beam is Ee = 28 GeV and of the proton beam Ep = 820 GeV. One electron is observed to scatter at the angle θ = 120° and its energy is measured to be E'e = 223 GeV. Calculate the centre of mass energy and the kinematical variables Q2, x, ν and W.

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