The velocity of a 1.2-kg particle is given by v = 1.5t 3 i + (2.4
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The velocity of a 1.2-kg particle is given by v = 1.5t3i + (2.4 − 3t2)j + 5k, where v is in meters per second and the time t is in seconds. Determine the linear momentum G of the particle, its magnitude G, and the net force R which acts on the particle when t = 2 s.
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Related Book For
Engineering Mechanics Dynamics
ISBN: 9781118885840
8th Edition
Authors: James L. Meriam, L. G. Kraige, J. N. Bolton
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