The elevator starts from rest at the first floor of the building. It can accelerate at 5
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The elevator starts from rest at the first floor of the building. It can accelerate at 5 ft/s² and then decelerate at 2 ft/s². Determine the shortest time it takes to reach a floor 40 ft above the ground. The elevator starts from rest and then stops. Draw the a-t, v-t, and s-t graphs for the motion.
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HIRS 40 ft
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Thus Thus When t 2145 s ...View the full answer
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Related Book For
Engineering Mechanics Statics & Dynamics
ISBN: 9780134895154
15th Edition
Authors: Russell C. Hibbeler
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