In this exercise, (F) is only assumed continuous on the right, and (Gleft(t^{-} ight))is the left-limit of

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In this exercise, \(F\) is only assumed continuous on the right, and \(G\left(t^{-}\right)\)is the left-limit of \(G\) at point \(t\). Prove that the process \(\left(M_{t}, t \geq 0\right)\) defined as

\[M_{t}=D_{t}-\int_{0}^{\tau \wedge t} \frac{d F(s)}{G(s-)}=D_{t}-\int_{0}^{t}\left(1-D_{s-}\right) \frac{d F(s)}{G(s-)}\]

is a \(\mathbf{D}\)-martingale.

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Mathematical Methods For Financial Markets

ISBN: 9781447125242

1st Edition

Authors: Monique Jeanblanc, Marc Yor, Marc Chesney

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