Find the value of k so that the given differential equation is exact. (6xy 3 + cos
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Find the value of k so that the given differential equation is exact.
(6xy3 + cos y) dx + (2kx2y2 - x sin y) dy = 0
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Given differential equation is in the form of M dx N dy ...View the full answer
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Related Book For
A First Course in Differential Equations with Modeling Applications
ISBN: 978-1305965720
11th edition
Authors: Dennis G. Zill
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