The linear systems in Problems 110 are in echelon form. Solve each by back substitution. x 1
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The linear systems in Problems 1–10 are in echelon form. Solve each by back substitution.
x1 - 5x2 + 2x3 - 7x4 + 11x5 = 0
x2 - 13x3 + 3x4 - 7x5 = 0
X4 - 5x5 = 0
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Related Book For
Differential Equations And Linear Algebra
ISBN: 9780134497181
4th Edition
Authors: C. Edwards, David Penney, David Calvis
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