The linear systems in Problems 110 are in echelon form. Solve each by back substitution. x 1

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The linear systems in Problems 1–10 are in echelon form. Solve each by back substitution.

x1 - 5x2 + 2x3 - 7x4 + 11x5 = 0

       x2 - 13x3 + 3x4 - 7x5 = 0

                          X4 -  5x5 = 0

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Related Book For  answer-question

Differential Equations And Linear Algebra

ISBN: 9780134497181

4th Edition

Authors: C. Edwards, David Penney, David Calvis

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