Consider water flow in a rectangular open channel of height 2 m and width 5 m containing

Question:

Consider water flow in a rectangular open channel of height 2 m and width 5 m containing water of depth 1.5 m. The hydraulic radius for this flow is

(a) 0.47 m

(b) 0.94 m

(d) 3.8 m

(e) 5 m

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The hydraulic radius R for a rectangular open channel can be calculated using the formula R A P Where R Hydraulic radius A Crosssectional area of the flow P Wetted perimeter In this case the crosssectional area A of the flow is the product of the width b and the depth h A b h A 5 m 15 m A 75 square meters The wetted perimeter P is the sum of the width b and twice the depth h because water is in contact with both the bottom and both sides of the channel P b 2h P 5 m 2 15 m P 5 m 3 m P 8 meters Now we can calculate ...View the full answer

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