The gravitational constant \(g\) is \(9.807 \mathrm{~m} / \mathrm{s}^{2}\) at sea level, but it decreases as you go up in elevation. A useful equation for this decrease in \(g\) is \(g=a-b z\), where \(z\) is the elevation above sea level, \(a=9.807 \mathrm{~m} / \mathrm{s}^{2}\), and \(b=3.32 \times 10^{-6} 1 / \mathrm{s}^{2}\). An astronaut "weighs" \(80.0 \mathrm{~kg}\) at sea level. [Technically this means that his/her mass is \(80.0 \mathrm{~kg}\).] Calculate this person's weight in \(\mathrm{N}\) while floating around in the International Space Station \((z=354 \mathrm{~km})\). If the Space Station were to suddenly stop in its orbit, what gravitational acceleration would the astronaut feel immediately after the satellite stopped moving? In light of your answer, explain why astronauts on the Space Station feel "weightless."