Starting with Eq. (3.95), derive in detail Eq. (3.96).

\[\begin{equation*}
d p+ho u d u=-\frac{1}{2} ho u^{2} \frac{4 f d x}{D} \tag{3.95}
\end{equation*}\]

\[\begin{equation*}
\frac{4 f d x}{D}=\frac{2}{\gamma M^{2}}\left(1-M^{2}\right)\left[1+\frac{1}{2}(\gamma-1) M^{2}\right]^{-1} \frac{d M}{M} \tag{3.96}
\end{equation*}\]