(A) Suppose that the mercury level in Example 6-2 is 7.8 mm higher in the arm open...

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(A) Suppose that the mercury level in Example 6-2 is 7.8 mm higher in the arm open to the atmosphere than in the closed arm. What would be the value of Pgas?

(B) Suppose Pbar. and Pgas are those described in Example 6-2, but the manometer is filled with liquid glycerol (d = 1.26 g/cm3) instead of mercury. What would be the difference in the two levels of the liquid?

Example 6-2

When the manometer in Figure 6-5(c) is filled with liquid mercury (d = 13.6 g/cm3) the barometric pressure is 748.2 mmHg, and the difference in mercury levels is 8.6 mmHg. What is the gas pressure Pgas?

Figure 6-5(c)

Pha n bar. P gas P gas Gas = Pbar. + AP (AP=-gxhxd <0) (c) The gas pressure is less than the barometric

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General Chemistry Principles And Modern Applications

ISBN: 9780132931281

11th Edition

Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette

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