At 2000 K, K c 0 154 for the reaction 2 CH 4 (g) C 2 H 2 (g) 3 H 2 (g) If a 1 00 L equilibrium mixture at 2000 K contains 0 10 mol each of CH 4 (g) and H 2 (g), (a) What is the mole fraction of C 2 H 2 (g) present (b) Is the conversion of CH 4 (g) to C 2 H 2 (g) favored at high or low pressures (c)...

a Calculate the mole fraction of C2H2g Firstwe need to calculate the equilibrium concentrations of a ...

At 2000 K, K c = 0.154 for the reaction 2 CH 4 (g) C 2

Question:

At 2000 K, K_c = 0.154 for the reaction 2 CH₄(g) ⇌ C₂H₂(g) + 3 H₂(g). If a 1.00 L equilibrium mixture at 2000 K contains 0.10 mol each of CH₄(g) and H₂(g),

(a) What is the mole fraction of C₂H₂(g) present?

(b) Is the conversion of CH₄(g) to C₂H₂(g) favored at high or low pressures?

(c) If the equilibrium mixture at 2000 K is transferred from a 1.00 L flask to a 2.00 L flask, will the number of moles of C₂H₂(g) increase, decrease, or remain unchanged?

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