Suppose that the reaction in Example 20-8 is first order with a rate constant of 0.12 min

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Suppose that the reaction in Example 20-8 is first order with a rate constant of 0.12 min-1. Starting with [A]0 = 1.00 M, will the curve for [A] versus t for the first-order reaction cross the curve for the second-order reaction at some time after t = 0? Will the two curves cross if [A]0 = 2.00 M? In each case, if the curves are found to cross, at what time will this happen?


Example 20-8

An alternative mechanism of the reaction 2 NO(g) + O2(g) → 2 NO2(g) follows. Show that this mechanism is consistent with the rate law, equation (20.24).

Fast: Slow: Overall: NO(g) + O(g) 0(g) NO3(g) + NO(g) 2 NO(g) + O(g) K-1 k NO3(g) 2 NO(g) 2 NO2(g)

Eq. 20.24

rate of reaction = k[NO][0] (20.24)

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Related Book For  answer-question

General Chemistry Principles And Modern Applications

ISBN: 9780132931281

11th Edition

Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette

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