Suppose you have available 2.50 L of a solution (d = 0.9767 g/mL) that is 13.8% ethanol

Question:

Suppose you have available 2.50 L of a solution (d = 0.9767 g/mL) that is 13.8% ethanol (CH₃CH₂OH), by mass. From this solution you would like to make the maximum quantity of ethanol-water antifreeze solution that will offer protection to -2.0 °C. Would you add more ethanol or more water to the solution? What mass of liquid would you add?

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