The aqueous solubility at 20 C of Ar at 1.00 atm is equivalent to 33.7 mL Ar(g),
Question:
The aqueous solubility at 20 °C of Ar at 1.00 atm is equivalent to 33.7 mL Ar(g), measured at 0 °C and 1.00 atm, per liter of water. What is the molarity of Ar in water that is saturated with air at 1.00 atm and 20 °C? Air contains 0.934% Ar by volume. Assume that the volume of water does not change when it becomes saturated with air.
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Step 1 Calculate the molarity of Ar in water at 20 C and 1 atm The aqueous solubility of Ar at 20 C ...View the full answer
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Related Book For
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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