Suppose you add 35.6 mL of 0.578 M Ba(OH) 2 to 55.6 mL of 0.491 M H
Question:
Suppose you add 35.6 mL of 0.578 M Ba(OH)2 to 55.6 mL of 0.491 M H2SO4. What would be the concentrations of Ba2+ and SO42− in the final solution at 25°C? What would be the pH of this solution?
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First note that only the first proton of H 2 SO 4 acts as a strong acid The net ionic equation is Ba ...View the full answer
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