(a) The reaction of CsF, I 2 O 5 and IF 5 at 435K leads to Cs...
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(a) The reaction of CsF, I2O5 and IF5 at 435K leads to Cs2IOF5. When the amount of CsF is halved, the product is CsIOF4. Write balanced equations for the reactions. Are they redox reactions?
(b) Using data in Fig. 17.14, calculate ΔG°(298 K) for the reaction:
Comment on the fact that the reaction does not occur at 298 K.
(c) Chlorine dioxide is the major bleaching agent in the pulp industry. While some statistics for bleaching agents list ClO2, others give NaClO3 instead. Suggest reasons for this difference.
Figure 17.14.
Transcribed Image Text:
4[C103] (aq) = 3[C104]¯¯(aq) + Cl¯ (aq)
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a Balanced equations for the reactions Reaction at 435K2 CsF I2O5 5 IF5 Cs2IOF5 When the amount of CsF is halvedCsF I2O5 4 IF5 CsIOF4 2 F2 Regarding w...View the full answer
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