Given that K sp for AgI is 8:51 10 17 , and E o Ag +
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Given that Ksp for AgI is 8:51 × 10−17, and EoAg+/Ag = +0:80 V, calculate Eo for the reduction step:
Hence confirm the statement in Section 8.3 that reduction of silver(I) when in the form of solid AgI is thermodynamically less favourable than reduction of AgCl.
Transcribed Image Text:
AgI (s) +eAg(s) + I¯ (aq)
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To calculate the standard reduction potential E for the reduction step of AgI we can use the Nernst equation E E RT nF lnQ Where E Standard cell poten...View the full answer
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