The emission spectrum of an Sm(III) complex contains sharp maxima in the range 525725 nm. The emitting

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The emission spectrum of an Sm(III) complex contains sharp maxima in the range 525–725 nm. The emitting state is 4G5/2, and transitions are to the 6HJ states for J = 11/2. 9/2, 7/2 and 5/2.

(a) Determine the ground state term for Sm3+, showing clearly how to determine values of S, L and J. 

(b) Use the information in the question and your answer to (a) to draw an energy level diagram showing the emission transitions. Which transition is at the
shortest wavelength? 

(c) What other 4G5/26HJ transitions are possible? Suggest a reason why emission maxima arising from these transitions are not observed in the 525–725 nm region.

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Related Book For  answer-question

Inorganic Chemistry

ISBN: 9781292134147

5th Edition

Authors: Catherine Housecroft

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