The reaction of trans-[Pt(PEt 3 ) 2 PhCl] with the strong nucleophile thiourea (tu) in MeOH follows
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The reaction of trans-[Pt(PEt3)2PhCl] with the strong nucleophile thiourea (tu) in MeOH follows a 2-term rate law with
A plot of kobs against [tu] is linear with the line passing close to the origin. Rationalize these observations.
Transcribed Image Text:
kobs = k₁+k₂[tu].
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The rate law for the reaction of MeOH methanol is given by Rate kTu2 where Tu represents the concent...View the full answer
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