The equation of motion for a particle moving on a rotating circular frame (Figure SP12.45) is [ddot{theta}+frac{g}{R}left(sin

Question:

The equation of motion for a particle moving on a rotating circular frame (Figure SP12.45) is

\[\ddot{\theta}+\frac{g}{R}\left(\sin \theta-\frac{\omega^{2}}{g} \cos \theta\right)=0\]

image text in transcribed

(a) Determine the equilibrium points.

(b) Classify the equilibrium points and determine their stability for

(i) \(\frac{\omega^{2}}{g}=0.5\)

(ii) \(\frac{\omega^{2}}{g}=1\)

(iii) \(\frac{\omega^{2}}{g}=1.5\)

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: