The equation of motion for a particle moving on a rotating circular frame (Figure SP12.45) is [ddot{theta}+frac{g}{R}left(sin
Question:
The equation of motion for a particle moving on a rotating circular frame (Figure SP12.45) is
\[\ddot{\theta}+\frac{g}{R}\left(\sin \theta-\frac{\omega^{2}}{g} \cos \theta\right)=0\]
(a) Determine the equilibrium points.
(b) Classify the equilibrium points and determine their stability for
(i) \(\frac{\omega^{2}}{g}=0.5\)
(ii) \(\frac{\omega^{2}}{g}=1\)
(iii) \(\frac{\omega^{2}}{g}=1.5\)
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: