Use a three-element, finite-element model to approximate the steady-state response of the system of Figure P11.16.

\[ \begin{array}{lll} L_{1}=2.1 \mathrm{~m} & L_{2}=1.0 \mathrm{~m} & I=0.25 \mathrm{~kg} \cdot \mathrm{m}^{2} \\ G_{1}=40 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2} & G_{2}=80 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2} & T_{0}=100 \mathrm{~N} \cdot \mathrm{m} \\ J_{1}=1.8 \times 10^{-5} \mathrm{~m}^{4} & J_{2}=4.3 \times 10^{-6} \mathrm{~m}^{4} & \omega=500 \mathrm{rad} / \mathrm{s} \\ ho_{1}=5000 \mathrm{~kg} / \mathrm{m}^{3} & ho_{2}=7000 \mathrm{~kg} / \mathrm{m}^{3} & \end{array} \]

Use two elements for \(A B\) and one element for \(B C\)

FIGURE P11.16

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A m + 1.1 B C To sincot Use two elements for AB and one element for BC