If R is a regular expression, let R {m,n} represent the expression R m R m+1
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If R is a regular expression, let R{m,n} represent the expression
Rm ∪ Rm+1 ∪ · · · ∪ Rn.
Show how to implement the R{m,n} operator, using the ordinary exponentiation operator, but without “· · · ”.
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The Rmn operator represents the expression Rm Rm1 Rn This can ...View the full answer
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