Let C = {G, x| G is a CFG x is a substring of some y
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Let C = {〈G, x〉| G is a CFG x is a substring of some y ∈ L(G)}. Show that C is decidable. An elegant solution to this problem uses the decider for ECFG.
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To show that C is decidable we need to show that there is an algorithm that can determine given a CF...View the full answer
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