Question:
Your company manufactures hemodialyzers that have the characteristics described in Example 8.3. A colleague in the company has proposed replacing the membranes with better ones, which have the same thickness, area, and porosity but for which the urea diffusivity in the membrane is 2.7×10−5 cm2/s. Assuming that the average concentrations of urea in the blood and dialysate are the same as with the old membranes, by what percentage would the new membranes increase the urea removal rate? In terms of resistances, explain why this turns out to be such a small improvement.
Transcribed Image Text:
EXAMPLE 8.3
SOLUTION
In patients with severe kidney disease, urea must be removed from the blood with a "hemodialyzer."
In that device, the blood passes by special membranes through which urea can pass. A salt solution
("dialysate") flows on the other side of the membrane to collect the urea and to maintain the de-
sired concentrations of vital salts in the blood. One geometry for hemodialyzer design is with flat
membranes in a rectangular system. For such a geometry, consider the following typical values:
Blood side:
mass-transfer coefficient for the urea
average urea concentration within the dialyzer
Dialysate side:
mass-transfer coefficient for the urea
average urea concentration within the dialyzer
Membrane:
thickness
diffusivity of urea in the membrane
total membrane area
porosity
a. From Equation 8.5, the initial removal rate is
Cureablood
Nurea =
a. Based on these values, what is the initial removal rate of urea? (Note: This rate will decrease
as the urea concentration in the blood decreases.)
1
hm.blood-sideA
b. One might be tempted to try to increase the removal rate of urea by developing better hemodi-
alyzer membranes. Based on analysis of these characteristics, is such an effort justified?
(0.0019 cm/s) (1.2m²)
1000L
Axmem
Durea, memAE pore
:) (₁
b. The three resistances of importance are
+
m³
1
hm.blood-side
Axmem
Durea mema Epore
Cureadialyse
1m
100 cm
0.02
0.0016 cm
+
(1.8 x 10-5 cm²/s) (1.2m²)(0.2)
+
0.003 gmol /L
0.0019 cm/s
0.020 gmol/L
60s
-
min
0.0011 cm/s
0.003 gmol/L
0.0016 cm
1.8 x 10-5 cm²/s
1.2 m²
20%
hm.dialysate-sideA
1
(0.0019 cm/s) (12,000 cm²)
+
= 0.0658mol
min
1
1
hm.dialysate-sideA (0.0011 cm/s) (12,000 cm²)
(0.0011 cm/s) (1.2m²)
0.0016 cm
(1.9 x 10-5cm²/s) (12,000 cm²) (0.2)
0.0439
S
cm-
= 0.0370
S
= 0.0758
cm³
S
cm
Improvement of the membranes would increase the transfer somewhat, since its resistance is
significant relative to the other resistances. But the greatest potential to increase the removal
rate is on the dialysate side, which has the largest resistance.