A vessel contains (6 mathrm{~m}^{3}) of air at a pressure of (500 mathrm{kPa}). If one-fifth of the

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A vessel contains \(6 \mathrm{~m}^{3}\) of air at a pressure of \(500 \mathrm{kPa}\). If one-fifth of the air be removed by an air pump, what will be the pressure of the remaining air, the temperature being constant? We are given that characteristic gas constant, \(R=0.287 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}\).

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