Sucrose (left(mathrm{C}_{12} mathrm{H}_{22} mathrm{O}_{11} ight)) burns at (25^{circ} mathrm{C}) to form (mathrm{CO}_{2}) gas and liquid (mathrm{H}_{2} mathrm{O}),

Question:

Sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) burns at \(25^{\circ} \mathrm{C}\) to form \(\mathrm{CO}_{2}\) gas and liquid \(\mathrm{H}_{2} \mathrm{O}\), releasing \(5,640,000\) \(\mathrm{kJ} / \mathrm{kmol}\) of heat according to the equation

\[ \mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(\mathrm{~s})+12 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 12 \mathrm{CO}_{2}(\mathrm{~g})+11 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+5,640,000 \mathrm{~kJ} / \mathrm{kmol} \]

Determine the enthalpy of formation of sucrose.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: