The temperature dependence of vapour pressure of an organic compound is given by [ log P=-frac{834.13}{T}+1.75 log

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The temperature dependence of vapour pressure of an organic compound is given by

\[ \log P=-\frac{834.13}{T}+1.75 \log T-8.375 \times 10^{-3} T+5.324 \]

Estimate the enthalpy of vaporization at its boiling point, $-103.9^{\circ} \mathrm{C}$.

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Introduction To Chemical Engineering Thermodynamics

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Authors: HALDER

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Question Posted: May 02, 2024 01:47 AM

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The temperature dependence of vapour pressure of an organic compound is given by [ log P=-frac{834.13}{T}+1.75 log

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From Eq 660 we get fracd ln Pd TfracDelta HR T2 The vapour pressure of t...View the full answer

Introduction To Chemical Engineering Thermodynamics

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