Differentiating with respect to (p) on both sides of the equation [sum_{x=1}^{infty} p(1-p)^{x-1}=1] show that the geometric
Question:
Differentiating with respect to \(p\) on both sides of the equation
\[\sum_{x=1}^{\infty} p(1-p)^{x-1}=1\]
show that the geometric distribution
\[f(x)=p(1-p)^{x-1} \quad \text { for } x=1,2,3, \ldots\]
has the mean \(1 / p\).
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Probability And Statistics For Engineers
ISBN: 9780134435688
9th Global Edition
Authors: Richard Johnson, Irwin Miller, John Freund
Question Posted: