Using Equation (7.28), prove that (-r_{1}(x)=frac{1}{6} ho_{3} H_{2}(x)) and [-r_{2}(x)=frac{1}{24} ho_{4} H_{3}(x)+frac{1}{72} ho_{3}^{2} H_{5}(x) .] d (x)pk(x)
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Using Equation (7.28), prove that \(-r_{1}(x)=\frac{1}{6} ho_{3} H_{2}(x)\) and \[-r_{2}(x)=\frac{1}{24} ho_{4} H_{3}(x)+\frac{1}{72} ho_{3}^{2} H_{5}(x) .\]
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d (x)pk(x) = (x)rk(x), dx (7.28)
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