Show that (mathbb{E}^{mathscr{G}} 1=1) if, and only if, (left.muight|_{mathscr{G}}) is (sigma)-finite. Find a counterexample showing that (mathbb{E}^{mathscr{G}}

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Show that \(\mathbb{E}^{\mathscr{G}} 1=1\) if, and only if, \(\left.\muight|_{\mathscr{G}}\) is \(\sigma\)-finite. Find a counterexample showing that \(\mathbb{E}^{\mathscr{G}} 1 \leqslant 1\) is, in general, the best possible.

[use \(p=2\) and \(\mathbb{E}^{\mathscr{G}}=\mathbb{E}^{\mathscr{G}}\).]

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