When the trial vector [vec{X}^{(1)}=left{begin{array}{l}1 1 1end{array} ight}] is used for the solution of the eigenvalue problem,
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When the trial vector
\[\vec{X}^{(1)}=\left\{\begin{array}{l}1 \\1 \\1\end{array}\right\}\]
is used for the solution of the eigenvalue problem,
\[\left[\begin{array}{lll}1 & 1 & 2 \\1 & 2 & 2 \\1 & 2 & 3\end{array}\right] \vec{X}=\lambda \vec{X}\]
the next trial vector, \(\vec{X}^{(2)}\), given by the matrix iteration method is
a. \(\left\{\begin{array}{l}3 \\ 5 \\ 6\end{array}\right\}\)
b. \(\left\{\begin{array}{l}1 \\ 1 \\ 1\end{array}\right\}\)
c. \(\left\{\begin{array}{l}3 \\ 3 \\ 3\end{array}\right\}\)
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