The potential energy of a mass (m) on the end of a Hooke's-law spring of force constant

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The potential energy of a mass \(m\) on the end of a Hooke's-law spring of force constant \(k\) is \((1 / 2) k x^{2}\). if the maximum speed of the mass with this potential energy is \(v_{0}\), what are the turning points of the motion?

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Related Book For  answer-question

Modern Classical Mechanics

ISBN: 9781108834971

1st Edition

Authors: T. M. Helliwell, V. V. Sahakian

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