By comparison with the series and is convergent and 1/2 100 =2[1/k(k 1)]

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By comparison with the series

100 =2[1/k(k  1)]

and

-2[1/k(k+1)], show that S = -2(1/k)

is convergent and 1/2

(In fact, Ex-(1/) = S + 1 = .) k

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