Find the equation of the tangent to the curve x 2 3xy 2y 2 3 at the point (1, 2) and the equation of the normal to the curve y x 3 x 2 at the point (1, 0) Find the distance of the point of intersection of these lines from the point (1, 2) ...

x3xy 2y 3 So differentiating 2x 3y3x 4y 0 at 1 2 4 5 and the equation of the tange ...

Find the equation of the tangent to the curve x 2 3xy + 2y 2 =

Question:

Find the equation of the tangent to the curve x² – 3xy + 2y² = 3 at the point (1, 2) and the equation of the normal to the curve y = x³ – x² at the point (1, 0). Find the distance of the point of intersection of these lines from the point (–1, 2).

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