Show that if is a complex cube root of unity, then 2 + +
Question:
Show that if ω is a complex cube root of unity, then ω2 + ω + 1 = 0. Deduce that
Hence show that the three roots of
Express the remaining two roots in terms of u, v and ω and find the condition that all three roots are real.
Transcribed Image Text:
(x + y + z)(x + wy + wz)(x + wy + wz) = = x3 + y3 + z3 - 3
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So Let 23 ej23 Then 43 23 02 43 23 0 a w w w 2 cos 2 1 x y zx...View the full answer
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