The trapezium rule estimate for 1 0 e x2 dx with h = 0.25 is 1.490
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The trapezium rule estimate for ∫10ex2dx with h = 0.25 is 1.490 68 to 5dp. Estimate the size of the global truncation error in this approximation and show that
What value of h will give an answer correct to 4dp?
Transcribed Image Text:
1.40 < = et dx < 1.48 0
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